bitGet problem
- 
					
					
					
					
 I ran this code segment and expected a "1" but I get a "0". result = bitGet (0x11111111111, 3) 
 drawtext (33,333,32, white, result)Any ideas? Thanks. 
- 
					
					
					
					
 @faz808 said in bitGet problem: 0x11111111111 Isn't 0x11111111111 in hex 0001 0001 0001 0001 0001 0001 0001 0001 0001 0001 0001 in binary in which case bit 3 is indeed 0? 
- 
					
					
					
					
 When you start a number with 0xthat means you're using a hexidecimal notation (so base 16). So0x11111111111in base 10 (our counting system) would be: 1172812402961
 In binary (base 2) it would be:10001000100010001000100010001000100010001So even though in hexidecimal the value is all 1's, in binary that's not the case. The documentation of bitGet doesn't strictly specify it, but I'm assuming bit 0 is the last bit, bit 1 is the one to the left of it, so that would mean that bit 3 would be "1 0001" a zero indeed.Hope that helps :) 
- 
					
					
					
					
 Pianofire beat me to it :P 
- 
					
					
					
					
 You are right the documentation isn't very clear but it seems to start at the least significant bit with a start index of 0 
- 
					
					
					
					
 Seems to be so. In the end all the necessary information is actually there (and the example code shows that bit 0 is used to decide if the number is even or odd), but you need to process all the information to get to it :) 
- 
					
					
					
					
 Of course ! 
 In my example,
 bit 0 = 1
 bit 1 = 0
 bit 2 = 0
 bit 3 = 0
 bit 4 = 1I forgot to convert my required binary number ( 11111111) to hex.. result = bitGet (0xff, 3) 
 drawtext (33,333,32, white, result)
 result = 1 asv expectedBrain now in gear. Thanks for the help. 
- 
					
					
					
					
 I'm wondering how this is "beginners". (not complaining btw) 
 Must mean I'm in the ultra beginners category ;)
- 
					
					
					
					
 Well you can be an experienced programmer but still a beginner at Fuze 
- 
					
					
					
					
 Very true, ..facepalm.. 
- 
					
					
					
					
 Is there any way to actually use a binary number in fuze without converting it. 
- 
					
					
					
					
 @xevdev I think it depends what you are trying to do if you want to replace your code by binary coding i dont think that works in fuze 
- 
					
					
					
					
 I'm not sure what you mean by us a binary numberin this case?
- 
					
					
					
					
 @petermeisenstein in this question they used a hexadecimal number ( base 16 ) by putting an x in a number as in 0x000001 giving 1 in decimal ( base 10 ) so I was wondering if I put some other letter , I've used % in other languages , to denote that it's a binary number ( base 2 ) 
- 
					
					
					
					
 @xevdev So i am not good at maths so I am sorry for any wrong thing what I say now. Isnt % the modulo I dont know if you say modulo in english. 
- 
					
					
					
					
 @petermeisenstein yes in fuze it is and I wrote my own mod function because I was expecting a function name not a symbol . So each language is different . 
- 
					
					
					
					
 @xevdev 
 And you are dealing with binary stuff in fuze very cool. Back to the roots of codeing
- 
					
					
					
					
 @petermeisenstein not if there's no way to put a binary number in to my code so I'll use 
 Bin = "10110010"
 If bin [0] = "1" then print("true")
 And because the first digit is 1 it will print true
 I think ?
 Got caught out again use
 If bin [0] ==
 Double equals
- 
					
					
					
					
 @xevdev Yeah I would also say maybe it helps you there is strcontains and other string stuff in fuze. Are you programming a ROM for a cpu emulator ? 
- 
					
					
					
					
 No I just want a binary number to use as a bitmask 
 And the code above doesn't work which is funny because I just wrote a whole program which uses something similar to that.
 
			
		 
			
		 
			
		