Unexpected fun (or fun facts)
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How do mathematicians deal with constipation?
They sit down and work it out with a pencil.
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what is a computers favorite food?... bits and chips
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Depending on your integer size 4294967297 + 4294967297 = 2 ;-) also you can get over it if you use int() to define your integer value.
(further down in the code you need aupdate()andsleep(10), not shown in the screenshot)
We seem to have 4 bytes available if we use a normal int assignment (not over the int() return value).
FFFF FFFF = 0 = 4294967296 = 2^32
Maybe int() returns a 64 bit integer? -
Yes, Fuze integers are 64 bit signed values, but the constant literals (numbers typed into the code editor) are 32 bit signed values. It is somewhat unusual for literals to be a smaller type than the variables they are assigned to. It makes for some interesting code if you want to use larger integers.
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...so if you do ’x = 4294967296
y = x+x
Print(y)’You’ll get the right answer?
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@toxibunny well not wrong, but probably not what you would expect. The number is stored in x as 0. So the result will be zero. @Gothon mentioned that the editor or interpreter is assigning only
2 bytes4 bytes for the number you type in the editor. If you generate that number with a function like int() and pow() you get the right value into x and it will show correctly. (Hope i got that right) -
What if x was set to be 4294967295?
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@toxibunny said in Unexpected fun (or fun facts):
What if x was set to be 4294967295?
You will get 4294967295 + 4294967295 = -2 because 4294967295 = 2^32 - 1. Valid values for 32 bit (4 byte) signed numbers go from -2^31 to 2^31 - 1 (-2147483648 to 2147483647), anything outside that range wraps around. Eg, 2147483648 = -2147483648
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I asked my lawyer if it was a crime to throw Sodium Chloride at a person.
Lawyer: yes, it's assault
Me: I know it's a salt but is it a crime?!? -
So I told my boss there were some bugs in the server and he hired an exterminator to spray it down
