bitGet problem

pianofire

0x11111111111

Isn't 0x11111111111 in hex ‭0001 0001 0001 0001 0001 0001 0001 0001 0001 0001 0001‬ in binary in which case bit 3 is indeed 0?

PB____

When you start a number with 0x that means you're using a hexidecimal notation (so base 16). So 0x11111111111 in base 10 (our counting system) would be: 1172812402961
In binary (base 2) it would be: 10001000100010001000100010001000100010001

So even though in hexidecimal the value is all 1's, in binary that's not the case.

The documentation of bitGet doesn't strictly specify it, but I'm assuming bit 0 is the last bit, bit 1 is the one to the left of it, so that would mean that bit 3 would be "10001" a zero indeed.

Hope that helps :)

PB____

Pianofire beat me to it :P

pianofire

You are right the documentation isn't very clear but it seems to start at the least significant bit with a start index of 0

PB____

Seems to be so. In the end all the necessary information is actually there (and the example code shows that bit 0 is used to decide if the number is even or odd), but you need to process all the information to get to it :)

faz808

Of course !
In my example,
bit 0 = 1
bit 1 = 0
bit 2 = 0
bit 3 = 0
bit 4 = 1

I forgot to convert my required binary number ( 11111111) to hex..

result = bitGet (0xff, 3)
drawtext (33,333,32, white, result)
result = 1 asv expected

Brain now in gear. Thanks for the help.

SteveZX81

I'm wondering how this is "beginners". (not complaining btw)
Must mean I'm in the ultra beginners category ;)

pianofire

Well you can be an experienced programmer but still a beginner at Fuze

SteveZX81

Very true, ..facepalm..

xevdev

Is there any way to actually use a binary number in fuze without converting it.

petermeisenstein

@xevdev I think it depends what you are trying to do if you want to replace your code by binary coding i dont think that works in fuze

PB____

I'm not sure what you mean by us a binary number in this case?

xevdev

@petermeisenstein in this question they used a hexadecimal number ( base 16 ) by putting an x in a number as in 0x000001 giving 1 in decimal ( base 10 ) so I was wondering if I put some other letter , I've used % in other languages , to denote that it's a binary number ( base 2 )

petermeisenstein

@xevdev So i am not good at maths so I am sorry for any wrong thing what I say now. Isnt % the modulo I dont know if you say modulo in english.

xevdev

@petermeisenstein yes in fuze it is and I wrote my own mod function because I was expecting a function name not a symbol . So each language is different .

petermeisenstein

@xevdev
And you are dealing with binary stuff in fuze very cool. Back to the roots of codeing

xevdev

@petermeisenstein not if there's no way to put a binary number in to my code so I'll use
Bin = "10110010"
If bin [0] = "1" then print("true")
And because the first digit is 1 it will print true
I think ?
Got caught out again use
If bin [0] ==
Double equals

petermeisenstein

@xevdev Yeah I would also say maybe it helps you there is strcontains and other string stuff in fuze. Are you programming a ROM for a cpu emulator ?

xevdev

No I just want a binary number to use as a bitmask
And the code above doesn't work which is funny because I just wrote a whole program which uses something similar to that.

pianofire

For the OCR code generator I have a couple of user functions:

// convert a decimal number to a binary string
function dec2bin(n,length_type)
  string byte=""
  if length_type > 0  then
    while int(n) > 0 loop
       nbit =  (n % 2)
       byte = str(nbit) + byte    
       n = n / 2
    repeat
    //pad to length_type bits...
    while len(byte) < length_type loop
      byte = "0" + byte
    repeat
  endif
return byte

// convert a binary string to decimal
function bin2dec( binaryString )
  int result = 0
  int i = 0
  for i = 0 to len( binaryString ) loop
    result *= 2
    result += int( binaryString[ i ] )
  repeat
return result

Credit to @faz808 for the first one