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    • PB____
      PB____ last edited by

      I'm not sure what you mean by us a binary number in this case?

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      • xevdev
        xevdev F @petermeisenstein last edited by

        @petermeisenstein in this question they used a hexadecimal number ( base 16 ) by putting an x in a number as in 0x000001 giving 1 in decimal ( base 10 ) so I was wondering if I put some other letter , I've used % in other languages , to denote that it's a binary number ( base 2 )

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        • P
          petermeisenstein F @xevdev last edited by

          @xevdev So i am not good at maths so I am sorry for any wrong thing what I say now. Isnt % the modulo I dont know if you say modulo in english.

          xevdev 1 Reply Last reply Reply Quote 0
          • xevdev
            xevdev F @petermeisenstein last edited by

            @petermeisenstein yes in fuze it is and I wrote my own mod function because I was expecting a function name not a symbol . So each language is different .

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            • P
              petermeisenstein F @xevdev last edited by

              @xevdev
              And you are dealing with binary stuff in fuze very cool. Back to the roots of codeing

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              • xevdev
                xevdev F @petermeisenstein last edited by xevdev

                @petermeisenstein not if there's no way to put a binary number in to my code so I'll use
                Bin = "10110010"
                If bin [0] = "1" then print("true")
                And because the first digit is 1 it will print true
                I think ?
                Got caught out again use
                If bin [0] ==
                Double equals

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                • P
                  petermeisenstein F @xevdev last edited by

                  @xevdev Yeah I would also say maybe it helps you there is strcontains and other string stuff in fuze. Are you programming a ROM for a cpu emulator ?

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                  • xevdev
                    xevdev F last edited by

                    No I just want a binary number to use as a bitmask
                    And the code above doesn't work which is funny because I just wrote a whole program which uses something similar to that.

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                    • pianofire
                      pianofire Fuze Team last edited by

                      For the OCR code generator I have a couple of user functions:

                      // convert a decimal number to a binary string
                      function dec2bin(n,length_type)
                        string byte=""
                        if length_type > 0  then
                          while int(n) > 0 loop
                             nbit =  (n % 2)
                             byte = str(nbit) + byte    
                             n = n / 2
                          repeat
                          //pad to length_type bits...
                          while len(byte) < length_type loop
                            byte = "0" + byte
                          repeat
                        endif
                      return byte
                      
                      // convert a binary string to decimal
                      function bin2dec( binaryString )
                        int result = 0
                        int i = 0
                        for i = 0 to len( binaryString ) loop
                          result *= 2
                          result += int( binaryString[ i ] )
                        repeat
                      return result
                      

                      Credit to @faz808 for the first one

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                      • xevdev
                        xevdev F last edited by

                        Thanks but

                        I simply want a binary number to be visible in my program that way I can easily change the bits

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                        • pianofire
                          pianofire Fuze Team last edited by

                          As far as I know there is no way to that currently

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                          • xevdev
                            xevdev F last edited by

                            That's ok the above works in a roundabout way

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